In an ap the sum of first n terms is 3n2/2

WebIf the sum of n terms of an A.P. be 3n2−n and its common difference is 6, then its first term is A 2 B 3 C 1 D None of these Solution The correct option is B 2 Sn = 3n2−n ⇒ S1 … WebThe sum of the first n term sofa an AP is ( 3 n 2 2 + 5 n 2). Find its nth term and the 25th term Advertisement Remove all ads Solution Let S denotes the sum of first n terms of the AP. ∴ s n = ( 3 n 2 2 + 5 n 2) ⇒ s n - 1 = 3 ( n - 1) 2 2 + 5 ( n - 1) 2 = 3 ( n 2 - 2 n + 1) 2 + 5 ( n - 1) 2 = 3 n 2 - n - 2 2 ∴ n th term pf the AP , a n

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WebDec 19, 2024 · Example 5: Find the sum of first 30 terms of an A.P. whose second term is 2 and seventh term is 22. Solution. Let a be the first term and d be the common difference of the given A.P. Then, a 2 = 2 and a 7 = 22 ⇒ a + d = 2 and a + 6d = 22 Solving these two equations, we get WebApr 1, 2024 · One of the most important and exam oriented question from arithmetic progression chapter as it was already asked in previous year paper of 2006 in which we have been asked to find the nth term and the 25th term, if the sum of the first n terms of an AP is (3n^2/2 + 5n/2) Book- RS Aggarwal, Class 10, chapter 5C, question no 6(ii). floor covering salary https://gomeztaxservices.com

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WebHere, y = Ioptimal , M = slope = = 2(c + d) + T (n − 2)=3(c + d) + T (n − 3) = . . . = (log2 n − 2), x = n, and the constant intercept c with n(c+d)+T (0) = c+n(c+d). This relationship satis- the y-axis needs to be determined. As the line passes fies for any positive integer constant, k. WebWe know that the nth term of AP is given by the formula a n = a+ (n−1)d. ⇒ 50 = 5+ (n−1)3 50 = 5+3n−3 50 = 3n+2 48 = 3n 16 = n By using the sum of AP formula, S n = n/2 (a 1 +a n) S n = 16/2 (5+50) S n = 8 (55) S n = 440 … WebApr 20, 2024 · Apr 20, 2024. The sum of the first n term of an AP,denoted by Sn is given by. Sn = n2 +8n. So. n th term of the series will be. tn = Sn −Sn−1 = n2 + 8n − ((n −1)2 +8(n − … floor covering pittsfield ma

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In an ap the sum of first n terms is 3n2/2

The sum of n terms of an A.P. is \\[3{n^2} + 5n\\] and its …

WebIn an A.P., the sum of first n terms is 3n2 2 + 13 2n. Find its 25th term. Solution n term sum = 3n²/2 + 13n/2 as we know that nth term = (Sum of nth term ) - ( sum of (n-1)th term) … WebMar 8, 2024 · The sum of first n terms of an AP is +5n. To find: Which Term of AP is 152. The sum of first 20 terms . Explanation: The sum of first 20 terms .= +5n. = +5×20 = 3 × 400 + 100 = 1300 Which Term of AP is 152. = +5n. = 3×1+5×1 = 8 That is first number = 8 = +5n. = 3 × 2² +5×2 = 12+10 =22 = + 22 = 8+ = 22-8 = 14 Common difference = - = 14-8 = 6

In an ap the sum of first n terms is 3n2/2

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WebThe sum of the first n terms of an arithmetic sequence is called an arithmetic series . Example 1: Find the sum of the first 20 terms of the arithmetic series if a 1 = 5 and a 20 = 62 . S 20 = 20 ( 5 + 62) 2 S 20 = 670. Example 2: Find the sum of the first 40 terms of the arithmetic sequence 2, 5, 8, 11, ⋯ . First find the 40 th term: WebAug 28, 2024 · Let the sum of n terms be given by Sn so Sn = 3n²/2+ 5n/2 S1 = 3 (1)²/2 + 5 (1)/2 = 3/2+5/2 => 4 so 1st term is 4 say 'a' Now S2 = 3 (2)²/2 + 5 (2)/2 = 6+5 => 11 Now a2 …

WebMay 11, 2024 · The sum of the first n terms of an AP is (3n^2/2 + 5n/2). Find its nth term and the 25th term. asked Apr 15, 2024 in Arithmetic Progression by Vevek01 ( 47.4k points) WebApr 20, 2024 · The sum of the first n term of an AP,denoted by # S_n# is given by #S_n=n^2+8n# So . n th term of the series will be. #t_n=S_n-S_(n-1)=n^2+8n-((n-1)^2+8(n-1))# #=>t_n=2n-1+8=2n+7# Inserting #n=1,2,3....# we get #"For "n=1tot_1=2*1+7=9# #"For "n=2tot_2=2*2+7=11# #"For "n=3tot_3=2*3+7=13# Hence first term #t_1=9# and common …

WebMar 22, 2024 · Transcript. Ex 9.2,13 If the sum of n terms of an A.P. is 3n2 + 5n and its mth term is 164, find the value of m. Let a1, a2, … an be the given A.P Given, Sum of n terms = 3n2 + 5n Sn = 3n2 + 5n Putting n = 1 in (1) S1 = 3 × 12 + 5 × 1 = 3 × 1 + 5 × 1 = 3 + 5 = 8 Sum of first 1 terms = First term ∴ First term = a1 = S1 = 8 Sn = 3n2 + 5n …(1) Putting n = 2 in … WebThe sum of the first n terms of an AP is (3n^2+6n). Find the nth term and the 15th term of this AP.CLASS-10PROGRESSIONS CBSETELANGANA AND ANDHRA PRADESH STAT...

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great north equipment lloydminsterWebApr 10, 2024 · Sum of first n terms of an AP. S n = n 2 [ 2 a + ( n − 1) d] Where a =1st term & d =common difference. Or, S n = n 2 [ a + a n] If there are only n terms in an AP, then. a n. … floor covering options for concreteWebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... floor coverings etcWebIf the sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, find the sum of th . . . . Find the sum of all the 11 terms of an AP whose middle most term is 30; Find the sum of last ten terms of the AP: 8, 10, 12,---, 126; Explore math program. Math worksheets and visual curriculum. Get Started. floor coverings batemans bayWebJan 8, 2024 · Math Army 81.9K subscribers In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term. In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th... floor covering options for living roomWebIf t5 and t12 of an AP are 14 and 35 respectively, find the first 5 terms of the AP. a) 2, 3, 9, 11, 14 ... 3n2 + 3o2 – p. 2 = 0. ii. m – 2o + q = 0. a. (i) is correct. b. (ii) is correct ... (ii) is correct. c. Both are correct. d. None are correct. 16.Find the sum of n terms of the series 1.2 + 3.22 + 5.23 + 7.24 + ..... a) (n – 1) 2n ... floor covering for kitchens and bathroomsWebin an AP the sum of first n terms is 3n2/2 + 13n/2 Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions The first term of two APs are equal and the ratios of … floor coverings in tacoma