Find the probability of getting 53 mondays
WebSo the probability of getting 53 Mondays in this case is 1/7. And if it's a leap year, we have 52 weeks and 2 days remaining. Hence, the probability of getting 53 Mondays in this case is 2/7. $\endgroup$ – deatheatersay. Apr 3, 2014 at 18:11. 1 $\begingroup$ Why not just use calendars to find out the day on which 1/1/2000 fell? WebOut of which, 2 combinations would given 53 Sundays. ⇒ Probability = 72. Was this answer helpful? 0. 0.
Find the probability of getting 53 mondays
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WebAnswers (1) There are four complete weeks in the month of January. There are three more extra days in the month. If the month starts on Saturday or Sunday or Monday, there are … WebApr 5, 2024 · Using those probability we can find the required answer. Complete step-by-step answer: We have to find that in a non-leap year the probability of getting 53 Sundays or 53 Tuesdays or 53 Thursday. We know that the number of days in a non-leap year is 365 days. Again, 1 year = 52 weeks = 52 × 7 = 364 days
WebMay 7, 2024 · Find the probability to getting 53 Mondays. probability; class-11; Share It On Facebook Twitter Email. 1 Answer +1 vote . answered May 7, 2024 by Ruksar03 … WebAug 7, 2024 · Perhaps you will say that probability of getting 52 Sundays in a leap year is 1. Your answer is not correct. Why? Think about the two remaining days. If from the remaining 2 days, 1 day is the Sunday, then there are 53 Sundays in a leap year. So, question is not ended at the stage that probability is 1.
WebApr 2, 2014 · Since 20871 = 329 × 52 + 71 × 53, there are 71 years with 53 Mondays, and so the probability that a year has 53 Mondays is 71 400 = 0.1775. Similar calculations … WebJul 17, 2024 · In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7. 2) ∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7. Advertisement.
WebThe 2 days can be as follows. (1) Sun M on (2) M on T ue (3) T ue W ed (4) W ed T hu (5) T hu F ri (6) F ri Sat (7) Sat Sun. So, 53rd Sunday can happen in 2 ways out of all the 7 …
instinct and reason privacy policyWebMay 26, 2024 · Best answer A leap year has 366 days (52 weeks + 2 days) That two days may be (sun, mon) (mon, tue) (tue, wed) (wed, thurs) (thurs, fri) (fri, sat) (sat, sun) ∴ n (S) = 7 Number of events for the occurrence of 53 Tuesdays and 53 Mondays, n (E) = 1 ∴ n(E) n(S) n ( E) n ( S) = 1 7 1 7 commented Dec 13, 2024 by b0164 (24 points) instinct and reason australiaWebApr 2, 2014 · Since 20871 = 329 × 52 + 71 × 53, there are 71 years with 53 Mondays, and so the probability that a year has 53 Mondays is 71 400 = 0.1775. Similar calculations over a 400 year cycle can show that the 13 th of a month is more likely to be a Friday than another other particular day. The question specifies that the year is between 2001 and … instinct and reason peopleWebQ: What is the probability of getting 53 Mondays in a leap year? Answer: C) 2/7 Explanation: 1 year = 365 days . A leap year has 366 days A year has 52 weeks. Hence there will be 52 Sundays for sure. 52 weeks = 52 x 7 = 364days 366 – 364 = 2 days In a leap year there will be 52 Sundays and 2 days will be left. These 2 days can be: 1. … jmh trailersWeb(Sat, Sun) Let E event of getting 53 Sundays & 53 Mondays. No. of favourable outcomes = 1 { (Sun, Mon)} Since 52 weeks has 52 Sundays & 52 Mondays & the extra 2 days must … jmh trucking wilmington ncWebDec 22, 2024 · In a non-leap year, the probability of having 53 Tuesdays or 53 Wednesdays is A. 1/7 B. 2/7 C. 3/7 D. none of these asked Sep 14, 2024 in Probability by Shyam01 ( 50.9k points) probability instinct and reason market researchWebProbability = (Number of favourable outcomes /Total number of events) Here, Number of favourable outcomes = 1 And, Total number of events are = 7 So, Probability = 1/7 Therefore, the probability of getting 53 sundays in a non leap year is 1/7. jmh trailers hamburg